The animation presents an example of beta-delayed particle emission. In this particular case the decay process consists of the following steps:
2615P11 → 2614Si12 + e+ + ν,
followed by proton emission (proton decay):
2614Si12 → 2513Al12 + p.
In the rollover image of the picture below you can see the decay processes starting from 26P. After the first β+ decay we get 100% 26S. Then the main branch is β+ decay again (denoted by ε in the chart). However thare is also a thin branch (~1%) where the 26S nucleus gets rid of its high excitation energy by emitting a proton rather than a γ photon. The product of this decay is 26Si which does not normally decay by proton emission although it is still relatively rich in protons (otherwise it would not show β+ activity after all). This shows that the excited state of the nucleus is important for the proton to conquer the Coulomb barrier.
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